Could anyone help me

Answer:1)[tex]m\angle 7 =65\°[/tex]  2)[tex]m\angle 4=115\°[/tex]3)[tex]m\angle 6=115\°[/tex]4)[tex]m\angle 1=65\°[/tex]5)[tex]m\angle 16=60\°[/tex]6)[tex]m\angle 18=60\°[/tex]7)[tex]m\angle 21=120\°[/tex]8)[tex]m\angle 10=55\°[/tex]9)[tex]m\angle 11=125\°[/tex]10) [tex]m\angle 12=55\°[/tex]Step-by-step explanation:Given:[tex]e\parallel m[/tex] and [tex]p\ and\ q[/tex] are traversals.[tex]m\angle 3=65\°[/tex][tex]m\angle 15 =120\°[/tex]1) [tex]m\angle 7 = m\angle 3 =65\°[/tex]       [corresponding angles]2)[tex]m\angle 4= 180\°-m\angle 3 =180\°-65\°=115\°[/tex] [As [tex]m\angle 4+m\angle 3=180\°[/tex] forming a linear pair]3)[tex]m\angle 6 = m\angle 4 =115\°[/tex]  [alternate exterior angles]4)[tex]m\angle 1 = m\angle 3 =65\°[/tex] [vertical angles]5)[tex]m\angle 16= 180\°-m\angle 15 =180\°-120\°=60\°[/tex] [As [tex]m\angle 15+m\angle 16=180\°[/tex] forming a linear pair]6)[tex]m\angle 18 = m\angle 16 =60\°[/tex] [alternate interior angles]7)[tex]m\angle 21 = m\angle 15 =120\°[/tex]  [alternate exterior angles][tex]m\angle 14 = m\angle 16 =60\°[/tex] [vertical angles][tex]m\angle 12+m\angle 7+m\angle 14=180\°[/tex] [Angle sum of triangle=180°][tex]m\angle 12=180\°-65\°-60\°=55\°[/tex][Plugging angle values in the above relation and solving for [tex]m\angle 12[/tex]8) [tex]m\angle 10 = m\angle 12 =55\°[/tex] [Vertical angles]9)[tex]m\angle 11= 180\°-m\angle 10 =180\°-55\°=125\°[/tex] [As [tex]m\angle 11+m\angle 10=180\°[/tex] forming a linear pair]10) [tex]m\angle 12 = m\angle 10 =55\°[/tex] [Vertical angles]